• Xstream 1.4.9
• Xstream 1.4.9 Jar Download
• Xstream 1.4.9 Download

FStream For Mac是一个简单的互联网广播播放器，让你听你最喜爱的广播电台。 Xdowns绿盟. FStream For Mac 1.4.9 - 互联网广播播放器.

• I would like to read input data from text file with fstream. But I don't know how to mix different type of get functions. I need 1,2,3 and 1,4,9 With the operator.
• FStream 1.4.9 add to watchlist send us an update. 8 screenshots: runs on: Mac OS X 10.4 or later (PPC & Intel) file size: 4.4 MB filename: fstreamFStream.zip main.
• I ask because gcc 4.8.1 & 4.9.X fails for me when both are specified:S Try specifying one and see if it works? – Brandon Dec 11 '14 at 15:16 @Brandon It fails because std::iosbase::in prevents the creation of a file if one doesn't exist.

Farmer John has N hills on his farm (1 <= N <= 1,000), each with an integer elevation in the range 0 .. 100. In the winter, since there is abundant snow on these hills, FJ routinely operates a ski training camp.

Unfortunately, FJ has just found out about a new tax that will be assessed next year on farms used as ski training camps. Upon careful reading of the law, however, he discovers that the official definition of a ski camp requires the difference between the highest and lowest hill on his property to be strictly larger than 17. Therefore, if he shortens his tallest hills and adds mass to increase the height of his shorter hills, FJ can avoid paying the tax as long as the new difference between the highest and lowest hill is at most 17.

If it costs x^2 units of money to change the height of a hill by x units, what is the minimum amount of money FJ will need to pay? FJ can change the height of a hill only once, so the total cost for each hill is the square of the difference between its original and final height. FJ is only willing to change the height of each hill by an integer amount.

PROGRAM NAME: skidesign

INPUT FORMAT:

SAMPLE INPUT (file skidesign.in):

INPUT DETAILS:

FJ’s farm has 5 hills, with elevations 1, 4, 20, 21, and 24.

OUTPUT FORMAT:

The minimum amount FJ needs to pay to modify the elevations of his hills so the difference between largest and smallest is at most 17 units.

SAMPLE OUTPUT (file skidesign.out):

OUTPUT DETAILS:

FJ keeps the hills of heights 4, 20, and 21 as they are. He adds mass to the hill of height 1, bringing it to height 4 (cost = 3^2 = 9). He shortens the hill of height 24 to height 21, also at a cost of 3^2 = 9.

ANALYSIS

Fatih Gelgi

The problem can be solved with different approaches. A simple idea is of course brute-force – try all possible elevations and find the minimum amount. We can try all possible values as follows: try the modification for elevation interval (0,17) then (1,18), (2,19), …, (83,100). For each elevation interval (i,i+17), we need to calculate the cost for each hill j:

1. If the elevation of hill j, say hill[j], is in the interval (i,i+17) then there is no cost.
2. If it is less than i then the cost increases by (i-hill[j])^2
3. If it is greater than i+17 then the cost increases by (hill[j]-(i+17))^2

The total cost for that interval will be the sum of the costs of modifying all hills.

For the sample input:

As you observed, it is unnecessary to try elevation intervals after (7,24) since the maximum height is 24. You may want to modify the solution to eliminate these type of redundancies although it is not necessary.

For each interval, scanning through all hill elevations require O(N) time. Since we try all possible intervals, the total time is O(NM) where M is the size of the elevation range. Since N=1000 and M=100 are very small, this brute-force approach is sufficient. A sample code is provided below:

Standard Template Library (STL) III - Iterators - 2020

Xstream 1.4.9

Iterators are used to step through the elements of collections of objects.

The major advantage of iterators is that they offer common interfaces for any container type. Understanding iterators is probably the key to understand the STL. Just as templates make algorithm independent of the type of data stored, iterators make the algorithms independent of the type of container used. They are, therefore, an essential component of the STL generic approach.

Algorithms should be independent of the data structure of the container itself as well as data type stored in the container. Templates provide a generic representation for the data type stored in a container. The iterators provide a generic representation of the process of moving through the values in a container.

Xstream 1.4.9 Jar Download

An iterator is an object that can navigate over elements of STL containers. All iterator represents a certain position in a container. To make it work, iterators have the following basic operations which are exactly the interface of ordinary pointers when they are used to iterator over the elements of an array.

1. Operator *
   Returns the element of the current position.
2. Operator ++
   Lets the iterator step forward to the next element. Most iterators also allow backward stepping with operator --.
3. Operator and !=
   Check whether two iterators represent the same position.
4. Operator =
   Assigns an iterator (the position of the element to which it refers.

Though pointers also have the same properties listed above, there is a difference between pointer and iterators. The difference is that iterators may be smart pointers which can iterate over more complicated data structures of containers. The internal behavior of iterators depends on the data structure over which they iterate. So, each container type provides its own kind of iterator. In fact, each container class defines its iterator type as a nested class. As a result, iterators share the same interface but have different types.

All container classes provide the same basic member functions that enable them to use iterators to navigate their elements. The most important two functions are:

1. begin()
   This returns iterator that represents the beginning of the elements in the container. The beginning is the position of the first element.
2. end()
   This returns an iterator that represents the end of the elements in the container. The end is the position behind the last element. This is also called a past-the-end iterator.

begin() and end() define a half-open range that includes the first element but exclude the last: [begin(),end()). A half-open range has two advantages:

1. We have a simple end criterion for loops that iterate over the elements: They simply march through until they meet end().
2. It avoids special handling for empty ranges. For empty ranges, begin is equal to end().

Different algorithms have different requirements for iterators. A find() algorithm needs the ++ operator to be defined so the iterator can step through the container. It does not need write access but it needs read access.

The sort() algorithm, on the other hand, requires random access so that it can swap the two non-adjacent elements.

The STL defines five iterators and describes its algorithms in terms of which kinds of iterator it needs.

1. Input Iterators
   The term input is used from the viewpoint of a program. In other words, information going from the container to the program is considered input. So, an input iterator is one that a program can use to read values from a container. Dereferencing an input iterator allows us to read a value from a container, but it does not allow us to alter the value. So algorithms that require an input iterator are algorithms that don't modify values of the container elements.

   One-way iterator. It can increment, but it can't back up.

   The data file:

   Output:

   Note that accumulate() is from <numeric> and the signature is:

   where the value is usually 0 and it gets the accumulated value over the specified range.

2. Output Iterators
   The term output indicates that the iterator is used for moving information from a program to a container. An output iterator is similar to an input iterator, except that dereferencing is guaranteed to allow a program to modify a value of container element but not to read it.

   Single-pass and write-only iterator.

3. Forward Iterators
   Forward iterators use only the ++ operators for navigating through a container. So a forward iterator can only go forward through a container one element at a time. Unlike input and output iterators, however, it necessarily goes through a sequence of values in the same order each time we use it.

   Multiple-pass iterator.

   The example below calculates squares for a given vector using ForwardIterator:

   Output:

4. Bidirectional Iterators
   A bidirectional iterator has all the features of a forward iterator and adds support for the two decrement operators (prefix and postfix).

   The following code checks if a string is a palindrome. The comparison starts from both ends using bidirectional iterator:

   Output:

5. Random Access Iterators
   Some of the algorithms such as sort() and binary search() require the ability to jump directly to an arbitrary element of a container. A canonical algorithm such as the sort() is using RandomAccessIterator:

   This type of iterator has all the features of a bidirectional iterator, plus it adds operations such as pointer addition that support random access and relational operations for those of a bidirectional iterators.

   The code below outputs a random element of a vector using the RandomAccessIterator:

   Output:

   Note that the ptrdiff_t is the type returned by the pointer subtraction operation between two pointers. THis is a signed integral type.

A const_iterator is equivalent to pointer to a constant. Iterator itself can change its value but not the underlying element. Another type of iterator is an iterator itself is a constant. This is quite useless since it can iterate among the element of the container. On the contrary, normal iterator can do anything: it can change its underlying elements, it can iterate through the elements of the container by changing its value. Below is an example:

Here is an example demonstrate the usage of iterators across several containers.

The output is:

Xstream 1.4.9 Download

STL's copy() function copies elements from a range to a location identified by an iterator:

The copy() function copies the elements in the range [first,last) into the range [result, result + (lat - first)). It returns an iterator pointing one past the last copied-to location, result + (last - first). The result should not be in the range [first, last).In other words, the target can't overlap the source.

The copy() algorithm can copy data from one container to another. For example, it can copy an array into a vector:

The copy() function overwrites existing data in the destination container. So, the container should be large enough to hold the copied elements. As a result, we can't simply use copy() to put data in an empty vector.

In the example, we displayed the elements after we copied the elements. If there is an iterator representing the output stream, we can use it with copy().STL provides us such an iterator with the ostream_iterator template. It is an adapter , which is a class or function that converts an interface to another interface.. The following lines are doing exactly that:

The myOutputIterator iterator now becomes an interface that allows us to use cout for display. The first template argument, int, indicates the data type being sent to the output stream.The second template argument, char, indicates that the output stream uses character type. The cout which is the first constructor argument identifies the output steam being used. The character string argument is a separator to be displayed after each item sent to the output stream.

We could use the iterator something like this:

It works like:

This ostream_iterator, the line says send 2013 and then a string ' ' to the output stream controlled by cout. With copy(), we can use the iterator like this:

This copies the entire v container to the output stream. In other words, it displays the all the contents of the v:

Actually, we do not need named iterator, myOutputIterator, for our display, and use an anonymous iterator:

Instead of